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JEE · NEET Previous Year Question

$To remove myopia (short sightedness) a lens of power 0.66 D is required. The distant point of the eye is approximately$

Topic: NEET PYQ

Answer: B. Full step-by-step solution below.

A $100 cm$
B $150 cm$
C $50 cm$
D $25 cm$

Correct answer: B

Solution

(b) Far point of the eye = focal length of the lens = \frac{100}{P} = \frac{100}{0.66} = 151 c m

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