A particle starting from rest, moves in a circle of radius ^ 'r '. It attains a velocity of v_0 m/s in the nth round. Its angular acceleration will be [NEET 2019]

Question

Accepted Answer

Correct answer: C. (c) From third equation of motion for circular motion ^2- _0^2=2 αθ ⇒ ( v_0r )^2-0=2 (2 πn ) ⇒ = v_0^24 πnr^2 rad/s^2

$A particle starting from rest, moves in a circle of radius^{’} r'. It attains a velocity of v_{0} m / s in the n th round. Its angular acceleration will be [NEET 2019]$

Solution

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