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JEE · NEET Previous Year Question

$For a common emitter configuration, if ' α' and ' β' have their usual meanings, the incorrect relation between ' α' and ' β'$

Topic: JEE PYQ

Answer: B. Full step-by-step solution below.

A $\frac{1}{α} = \frac{1}{β} + 1$
B $α = \frac{β}{1 - β}$
C $α = \frac{β}{1 + β}$
D $\frac{1}{β} = \frac{1}{α} - 1$

Correct answer: B

Solution

(b) α = \frac{I _{c}}{I _{e}}, β = \frac{I _{c}}{I _{b}}; I_{e} = I_{b} + I_{c} l = \frac{I _{e}}{I _{c}} = \frac{I _{b}}{I _{c}} + 1 \Rightarrow \frac{1}{α} = \frac{1}{β} + 1 \frac{1}{α} = \frac{1 + β}{β} \Rightarrow α = \frac{β}{1 + β} \Rightarrow \frac{1}{β} = \frac{1}{α} - 1

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