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JEE · NEET Previous Year Question

$The average energy possessed by an oscillator at a temperature 300 K is (Boltzmann constant = 1.38 \times 10^{- 23} JK^{- 1})$

Topic: JEE PYQ

Answer: D. Full step-by-step solution below.

A $2.14 \times 10^{- 2} J$
B $2.07 \times 10^{- 19} J$
C $4.14 \times 10^{- 21} J$
D $None$

Correct answer: D

Solution

(d) The average energy possessed by an oscillator, E = \frac{1}{2} K_{B} T = \frac{1}{2} \times 1.38 \times 10^{- 23} \times 300 = 2.07 \times 10^{- 21} J

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