The displacement of a particle along the ‐axis is given by =a sin^2 ωt. The motion of the particle corresponds to

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Correct answer: C. (c) =a sin^2 ωt=a ( 1- cos2 ωt2 ) ( cos2 =1-2 sin^2 ) = a2- a cos2 ωt2 Velocity, v= dx dt= 2 ωa sin2 ωt2= ωa sin2 ωt Acceleration, a= dv dt=2 ^2a cos2 ωt For the given displacement x=a sin^2 ωt , a ∝ is not satisfied. Hence, the motion of the particle is non-simple harmonic motion. Note: The given motion is a periodic motion with a time period 2 T=2 Mk

$The displacement of a particle along the χ ‐axis is given by χ = a si n^{2} ωt . The motion of the particle corresponds to$

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