The displacement of a particle executing SHM is given by x=3 sin ⁡(2 πt+ 4) where ' x ' is in metres and ' t ' is in seconds. The amplitude and maximum speed of the particle is

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Accepted Answer

Correct answer: A. (a) The given equation of SHM is x=3 sin ⁡(2 πt+ 4) Compare the given equation with standard equation of S.H.M. x= Asin ⁡ ( ωt+ ) we get, A=3 m , =2 s^-1 ∴ Maximum speed, v_ max= Aω=3 m 2 s^-1 =6 πms^-1

$The displacement of a particle executing SHM is given by x = 3 sin (2 πt + \frac{π}{4}) where ' x' is in metres and ' t' is in seconds. The amplitude and maximum speed of the particle is$

Solution

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