Two particles are executing simple harmonic motion of the same amplitude A and frequency ꞷ along the x-axis. Their mean position is separated by distance X_0 (X_0 A). If the maximum separation betw…

Question

Two particles are executing simple harmonic motion of the same amplitude A and frequency ꞷ along the x-axis. Their mean position is separated by distance X_0 (X_0 > A). If the maximum separation between them is (X_0 + A), the phase difference between their motion is:

Accepted Answer

Correct answer: B. (b) x1 = A sin(ωt + φ1) x2 = A sin(ωt + φ_2) x1 – x2 = A (2 sin( t+ _1+ _22) sin ( _1- _22 ) ) A = 2A sin ( _1- _22 ) _1- _22 = 6 ⇒ φ1 = 3

$Two particles are executing simple harmonic motion of the same amplitude A and frequency ꞷ along the x-axis. Their mean position is separated by distance X_{0} (X_{0} > A). If the maximum separation between them is (X_{0} + A), the phase difference between their motion is:$

Solution

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