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Mere Teacher · Previous Year Questions
NEET Physics · Simple Harmonic Motion · Set 6 (Q151-180)
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151.
For a body executing S.H.M.: (A) Potential energy is always equal to its K.E. (B) Average potential and kinetic energy over any given time interval are always equal. (C) Sum of the kinetic and potential energy at any point of time is constant. (D) Average K.E. in one time period is equal to average potential energy in one time period. Choose the most appropriate option from the options given below:
(1)(C) and (D)
(2)only (C)
(3)(B) and (C)
(4)only (B)
152.
Two simple harmonic motions are represented by y1=5[sin2πt+3cos2πt] and y2=5sin(2πt+4π). The ratio of their amplitudes is
(1)1:1
(2)2:1
(3)1:3
(4)3:1
153.
A second pendulum is placed in a space laboratory orbiting round the earth at a height ' 3R ' from the earth's surface. The time period of the pendulum will be ( R= radius of earth)
(1)zero
(2)32s
(3)4s
(4)infinite.
154.
Two S.H.Ms are represented by equations y1=0.1sin(100πt+3π) and y2=0.1cos(100πt)The phase difference between the speeds of the two particles is
(1)3π
(2)−6π
(3)+6π
(4)−3π
155.
A S.H.M. is represents by x = 52 (sin 2πt + cos 2πt). The amplitude of the S.H.M. is:
(1)10 cm
(2)20 cm
(3)52 cm
(4)50 cm
156.
In a simple harmonic oscillation, what fraction of total mechanical energy is in the form of kinetic energy, when the particle is midway between mean and extreme position.
(1)21
(2)43
(3)31
(4)41
157.
A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at distance 32Afrom equilibrium position. The new amplitude of the motion is.
(1)3A
(2)A3
(3)37A
(4)3A41
158.
A point mass oscillates along x-axis according to x=x0sin(ωt−6π). If the acceleration of the point mass is written as a=Asin(ωt+δ) then
(1)A=x0,δ=−6π
(2)A=xoω2,δ=−6π
(3)A=xoω2,δ=6π
(4)A=xoω2,δ=65π
159.
The displacement of a particle executing simple harmonic motion is given by x=2cos(t) where t is the time in seconds then the time period of the particle is
(1)π second
(2)2π second
(3)3π second
(4)0.5π second
160.
A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
(1)2π5
(2)54π
(3)32π
(4)π5
161.
A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 ms−2 at a distance of 5 m from the mean position. The time period of oscillation is
(1)2πs
(2)πs
(3)2 s
(4)1 s
162.
The displacement of a particle exceuting S.H.M. is x=asin(ωt−φ). Velocity of the particle at time t=ωφ is (cos0∘=1)
(1)ωcosϕ
(2)aω
(3)ωcos2ϕ
(4)-aωcos2ϕ
163.
If a spring of stiffness 'k' is cut into two parts 'A' and 'B' of length λA : λB = 2 : 3, then the stiffness of spring 'A' is given by:
(1)53k
(2)52k
(3)k
(4)25k.
164.
The position of a particle w.r.t. to origin varies according to the relation x=3sin100t+8cos250t. Which of the following is/are correct about this motion?
(1)The motion of the particle is not S.H.M.
(2)The amplitude of the S.H.M. of the particle is 6 units
(3)The amplitude of the resultant S.H.M. is 73 units
(4)The maximum displacement of the particle from the origin is 9 units
165.
When two displacements represented by y1=asin(ωt) and y2=bcos(ωt) are superimposed, the motion is
(1)simple harmonic with amplitude ba
(2)simple harmonic with amplitude a2+b2
(3)simple harmonic with amplitude 2(a+b)
(4)not a simple harmonic
166.
A pendulum oscillates simple harmonically if and only if (i) the size of the bob of pendulum is negligible in comparison with the length of the pendulum. (ii) the angular amplitude is less than 10∘.
(1)Both (i) and (ii) are correct.
(2)Both (i) and (ii) are incorrect.
(3)Only (i) is correct.
(4)Only (ii) is correct.
167.
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): Time period of a simple pendulum is longer at the top of a mountain than that at the base of the mountain. Reason (R): Time period of a simple pendulum decreases with increasing value of acceleration due to gravity and vice-versa. choose the most appropriate answer from the options given below:
(1)Both (A) and (R) are true and (R) is the correct explanation of (A)
(2)(A) is true but (R) is false
(3)(A) is false but (R) is true
(4)Both (A) and (R) are true but (R) is not the correct explanation of (A)
168.
A pendulum is hung from the roof of a sufficiently high building and is moving freely to and for like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s2 at a distance of 5 m from the mean position. The time period of oscillation is:
(1)2πs
(2)1 s
(3)2 s
(4)π s
169.
A uniform rod of length 1.8m suspended by an end is made to undergo small oscillations. Find the length of the simple pendulum having the mass and time period equal to that of the rod.
(1)3.6m
(2)1.2m
(3)2.4m
(4)4.2m
170.
The equation of simple harmonic progressive wave is given by Y=asin2π(bt−cx).The maximum particle velocity will be twice the wave velocity if
(1)c=πa
(2)c=2πa1
(3)c=πa1
(4)c=2πa
171.
A particle is executing simple harmonic motion with an amplitude of 2m. The difference in the magnitudes of its maximum acceleration and maximum velocity is 4. The time-period of its oscillation and its velocity when it is 1m away from the mean position are respectively
(1)2s,23ms−1
(2)227s,43ms−1
(3)722s,23ms−1
(4)744s,43ms−1
172.
A simple harmonic motion is given by y = 5 (sin 3πt + 3cos 3πt). What is the amplitude of motion if y is in m?
(1)100 cm
(2)5 m
(3)200 cm
(4)1000 cm
173.
A block resting on the horizontal surface executes S.H.M. in horizontal plane with amplitude A The frequency of oscillation for which the block just starts to slip is ( μ= coefficient of friction, g= gravitational acceleration)
(1)2π1Aμg
(2)4π1Aμg
(3)2πμgA
(4)4πμgA
174.
The time period of mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be
(1)T/4
(2)T
(3)T/2
(4)2T
175.
If two similar springs each of spring constant K1are joined in series, the new spring constant and time periodwould be changed by a factor:
(1)21,2
(2)41,22
(3)21,22
(4)41,2
176.
Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards withan acceleration g/2, the time period of pendulum will be:
(1)3T
(2)3T
(3)23T
(4)32T
177.
A damped harmonic oscillator has a frequency of 5 oscillations per second. The amplitude drops to half its value for every 10 oscillations. The time it will take to drop to 10001 of the original amplitude is close to:
(1)50s
(2)100s
(3)20s
(4)10s
178.
The maximum potential energy of a block executing simple harmonic motion is 25 J. A is amplitude of oscillation. At A/2, the kinetic energy of the block is
(1)37.5J
(2)9.75 J
(3)18.75 J
(4)12.5 J
179.
A particle executes simple harmonic motion according to the equation x(t)=Asin2(αt). If the time period of the SHM is 0.2s, then the value of α (in units of rad/s ) is
(1)2π
(2)10π
(3)5π
(4)2.5π
180.
The position vector of a particle moving in x-y plane is given by r = (A sinωt) i^ + (A cosωt) j^ then motion of the particle is: