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Mere Teacher · Previous Year Questions
NEET Physics · Simple Harmonic Motion · Set 7 (Q181-210)
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181.
Equation of simple harmonic progressive wave is given by y=a1sinωt±b1cosωt, then the resultant amplitude of the wave is (cos90∘=0)
(1)aba±b
(2)aba±b
(3)aba±b
(4)aba+b
182.
A point mass of 400g executes S.H.M. under a force F=−(10Nm−1)x. If it crosses the centre of oscillation with a speed of 10ms−1, the amplitude of motion is
(1)2m
(2)4m
(3)0.4m
(4)0.5m
183.
If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is 2x times its original time period. Then the value of x is [NEET 2024]
(1)3
(2)2
(3)23
(4)4
184.
A clock is designed based on the oscillations of a spring block system suspended vertically in the absence of air-resistance. Assume it shows the correct time when a spring of stiffness ' k ' and block of mass ' m ' are used. If the block is replaced by another block of mass 4m, choose the correct option.
(1)The clock runs slow by 0.5 s for every one second
(2)The clock runs fast by 0.5 s for every one second
(3)The clock runs fast by 1s for every one second
(4)The clock runs slow by 1s for every one second
185.
When two mutually perpendicular simple harmonic motions of same frequency, amplitude and phase are superimposed
(1)the resulting motion is uniform circular motion.
(2)the resulting motion is a linear simple harmonic motion along a straight line inclined equally to the straight lines of motion of component ones.
(3)the resulting motion is an elliptical motion, symmetrical about the lines of motion of the components.
(4)the two S.H.M. will cancel each other.
186.
The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is:
(1)6s
(2)8 s
(3)12s
(4)36 s
187.
A particle is executing S.H.M. of periodic time ' T '. The time taken by a particle in moving from mean position to half the maximum displacement is (sin30∘=0.5)
(1)2T
(2)4T
(3)8T
(4)12T
188.
A S.H.M. is represented by x=52(sin2πt+cos2πt). The amplitude of the S.H.M. is
(1)10 cm
(2)20 cm
(3)52cm
(4)50 cm
189.
The equation of motion of a particle performing linear S.H.M is x=5sin(4t−6π), where ' x ' is its displacement in cm. The velocity of the particle when its displacement is 3cm, is
(1)10cm/s
(2)16cm/s
(3)6cm/s
(4)8cm/s
190.
A particle is executing simple harmonic motion (SHM). The ratio of potential energy and kinetic energy of the particle when its displacement is half of its amplitude will be
(1)1:1
(2)1 : 3
(3)2 : 1
(4)1 : 4
191.
A particle performs linear S.H.M. At a particular instant, velocity of the particle is u and acceleration is α while at another instant velocity is v and acceleration is β(0<α<β). The distance between the two positions is
(1)α+βu2−v2
(2)α+βu2+v2
(3)α−βu2−v2
(4)α−βu2+v2
192.
If x, v and a denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period T, then, which of the following does not change with time?
(1)xaT
(2)aT + 2πv
(3)vaT
(4)a2T2 + 4π2v2
193.
The displacement of a particle along the x axis is given by x = asin2ꞷt. The motion of the particle corresponds to
(1)simple harmonic motion of frequency ꞷ/π
(2)simple harmonic motion of frequency 3ꞷ/2π
(3)non simple harmonic motion
(4)simple harmonic motion of frequency ꞷ/2π
194.
A bob of mass 'm' suspended by a thread of length l undergoes simple harmonic oscillations with time period T. If the bob is immersed in a liquid that has density 41 times that of the bob and the length of the thread is increased by 1/3rd of the original length, then the time period of the simple harmonic oscillations will be:-
(1)T
(2)23T
(3)43T
(4)34T
195.
When a particle of mass m is attached to a vertical spring of spring constant k and released, its motion is described by y(t)=y0sin2ωt, where y’ is measured from the lower end of unstretched spring. Then ω is
(1)y02g
(2)21y0g
(3)2y0g
(4)y0g
196.
A mass is suspended from a spring having spring constant ' K ' is displaced vertically and released, oscillates with period ' T '. The weight of the mass suspended is (g= gravitational acceleration)
(1)4π2KTg
(2)4π2KT2g
(3)2π2KTg
(4)2π2KT2g
197.
The resultant of two rectangular simple harmonic motions of the same frequency and unequal amplitudes but differing in phase by π/2 is:
(1)Simple harmonic
(2)Circular
(3)Elliptical
(4)Parabolic
198.
A clock pendulum having coefficient of linear expansion α=9×10−7/∘C has a period of 0.5s at 20∘C. If the clock is used in a climate where the temperature is 30∘C, how much time does the clock lose in each oscillation? (g= constant )
(1)25×10−7 s
(2)5×10−7s
(3)1.125×10−6s
(4)2.25×10−6s
199.
Two masses MA and MB are hung from two smngs of length lA and lB respectively. They are executing SHM with frequency relation fA=2fB, then relation
(1)lA=4lB, does not depend on mass
(2)lA=4lB, does not depend on mass
(3)lA=2lB and MA=2MB
(4)lA=2lB and MA=2MB.
200.
The function of time representing a simple harmonic motion with a period of ωπ is:
(1)sin(ωt)+cos(ωt)
(2)cos(ωt)+cos(2ωt)+cos(3ωt)
(3)sin2(ωt)
(4)3cos(4π−2ωt)
201.
Abode of massm is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass. When the mass m is slightly pulled down and released, it oscillates with a time period of 3 s. When the mass m is increased by 1 kg, the time period of oscillations becomes 5 s. The value of m in kg is
(1)43
(2)34
(3)916
(4)169
202.
A spring is stretched by 0.40m when a mass of 0.6kg is suspended from it. The period of oscillations of the spring loaded by 255g and put to oscillations is close to (g=10ms−2)
(1)11s
(2)48.6s
(3)0.82s
(4)4.86s
203.
A simple pendulum is oscillating with amplitude ' A ' and angular frequency ' ω '. At displacement ' x ' from mean position, the ratio of kinetic energy to potential energy is
(1)A2−x2x2
(2)x2x2−A2
(3)x2A2−x2
(4)xA−x
204.
Two pendulums begin to swing simultaneously. The first pendulum makes nine full oscillations when the other makes seven. The ratio of the lengths of the two pendulums is
(1)8149
(2)8164
(3)98
(4)97
205.
If x=5sin(πt+3π)m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are [NEET 2024]
(1)5cm,2s
(2)5m,2s
(3)5cm,1s
(4)5m,1s
206.
A particle executes SHM with amplitude 0.2m and time period 24s. The time required for it to move from the mean position to a point 0.1m from the mean position is
(1)2s
(2)3s
(3)8s
(4)12s
207.
A loop of radius R and mass m is placed in a uniform magnetic field B with its plane perpendicular to the field. Current I is flowing in it. Now loop is slightly rotated about its diameter and released. Find time period of oscillation.
(1)2lBπm
(2)lB2πm
(3)2πIBm
(4)πIBm
208.
A linear harmonic oscillator of force constant 2×106N/m and amplitude 0.01 m has a total mechanical energy of160 J. Its
(1)P.E. is 160 J
(2)P.E. is zero
(3)P.E. is 100 J
(4)P.E. is 120 J.
209.
A particle is subjected to two simple harmonic motions along x and y directions according to x=3sin100πt;y=4sin100πt Choose the correct option.
(1)Motion of particle will be elliptical, traversing in clockwise direction
(2)Particle will move on a straight line of slope 4/3
(3)Particle will have simple harmonic motion along x-axis with amplitude 5 units.
(4)Particle will transverse a hyperbola.
210.
A particle is vibrating in S.H.M. with an amplitude of 4cm. At what displacement from the equilibrium position is its energy half potential and half kinetic?