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JEE · NEET Previous Year Question

$The efficiency of a Carnot engine operating with reservoir temperature of 10 0^{o} Cand - 2 3^{o} C will be$

Topic: NEET PYQ

Answer: B. Full step-by-step solution below.

A $\frac{373 + 250}{373}$
B $\frac{373 - 250}{373}$
C $\frac{100 + 23}{100}$
D $\frac{100 - 23}{100}$

Correct answer: B

Solution

(b) Reservoir temperature (T_{1}) = 10 0^{o} C = 373 K and T_{2} = - 2 3^{o} C = 250 K. The efficiency of a Carnot engine η = \frac{T _{1} - T _{2}}{T _{1}} = \frac{373 - 250}{373} .

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