Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently the mean collision time between the gas molecules changes from _1to _2. If C_pC_v= for this gas then a good estimate…

Question

Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently the mean collision time between the gas molecules changes from _1to _2. If C_pC_v= for this gas then a good estimate for _2 _1 is given by

Accepted Answer

Correct answer: A. (a) relaxation time ( ) ∝ V T And T ∝ 1V^ -1 ∝V^1+ -12 ∝V^ 1+ 2 _f _i= ( 2VV )^ 1+ 2 _f _i= (2 )^ 1+ 2

$Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently the mean collision time between the gas molecules changes from τ_{1} to τ_{2} . If \frac{C _{p}}{C _{v}} = γ for this gas then a good estimate for \frac{τ _{2}}{τ _{1}} is given by$

Solution

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