A heat engine has an efficiency of ( 16 ). When the temperature of sink is reduced by 62^0C, its efficiency get doubled. The temperature of the source is:

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Accepted Answer

Correct answer: D. (d) =1- T_LT_H….(i) 2 =1- (T_L-62)T_H=1- T_LT_H+ 62T_H ⇒ = 62T_H ⇒ 16= 62T_H ⇒T_H=6 62=372K In ℃ => 372 − 273 = 99 °C

$A heat engine has an efficiency of (\frac{1}{6}) . When the temperature of sink is reduced by 6 2^{0} C, its efficiency get doubled. The temperature of the source is:$

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