A certain vector in the yz plane has a y-component of 12 m and a z-component of 8 m. It is then rotated in the yz plane so that its y-component is halved. Then its new z-component is approximately

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Correct answer: B. (b) : Let A be a vector in yz plane. Its y and z components are A_y=12 m ,A_z=8 m respectively. The magnitude of vector A is A= A_y^2+A_z^2= (12 )^2+ (8 )^2= 208 m When this vector is rotated in yz plane such that its y component becomes halved and its new z component be A_z^ '. Then A= ( A_y2 )^2+A_z^ '2 208= (6 )^2+A_z^ '2 Squaring both sides, we get 208= (6 )^2+A_z^ '2 orA_z^ '2=208-36=172A_z^ '= 172=13.11 m

$A certain vector in the yz plane has a y -component of 12 m and a z -component of 8 m . It is then rotated in the yz plane so that its y -component is halved. Then its new z -component is approximately$

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