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JEE · NEET Previous Year Question

$The equation of a stationary wave is y = 2 sin (\frac{πx}{15}) cos (48 πt) . The distance between a node and its next antinode is$

Topic: JEE PYQ

Answer: B. Full step-by-step solution below.

A $22.5 units$
B $7.5 units$
C $30 units$
D $1.5 units$

Correct answer: B

Solution

(b) From given equation, k = \frac{2 π}{λ} = \frac{π}{15} \Rightarrow λ = 30 Distance between node and next antinode x = \frac{λ}{4} ∴ x = \frac{λ}{4} = \frac{30}{4} = 7.5 units

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