A transverse wave is represented by y=A sin ( ωt- kx ) . For what value of the wavelength is the wave velocity equal to the maximum particle velocity?

Question

Accepted Answer

Correct answer: C. (c) The given wave equation is y=A sin ( ωt- kx ) Wave velocity, = k (i) Particle velocity, v_p= dy dt= Aωcos ( ωt- kx) Maximum particle velocity, (v_p )_ max= Aω (ii) According to the given question v= (v_p )_ max k= Aω (Using (i) and (ii)) 1k=A or 2 = Ak= 2 ) =2 A

$A transverse wave is represented by y = A sin (ωt - kx) . For what value of the wavelength is the wave velocity equal to the maximum particle velocity?$

Solution

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