Two waves are represented by the equations y_1 = a sin(ꞷt + kx + 0.57)m and y_2 = a cos(ꞷt + kx)m, where x is in meter and t in sec. The phase difference between them is:

Question

Accepted Answer

Correct answer: A. (a) y_1= asin ⁡ ( ωt+ kx+0.57 ) ∴ Phase , _1= ωt+ kx+0.57 y_2= acos ⁡ ( ωt+ kx )= asin ⁡( ωt+ kx+ 2) ∴ Phase , _2= ωt+ kx+ 2 Phase difference , = _2- _1 =( ωt+ kx+ 2)-( ωt+ kx+0.57)= 2-0.57 = (1.57-0.57 ) radian =1 radian

$Two waves are represented by the equations y_{1} = a sin(ꞷt + kx + 0.57)m and y_{2} = a cos(ꞷt + kx)m, where x is in meter and t in sec. The phase difference between them is:$

Solution

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