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JEE · NEET Previous Year Question

$Standing waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave velocity is 20 m / s, the frequency is$

Topic: NEET PYQ

Answer: A. Full step-by-step solution below.

A $5 Hz$
B $10 Hz$
C $2 Hz$
D $4 Hz$

Correct answer: A

Solution

(a) The frequency of standing wave, v = \frac{n}{2 l} v = \frac{5 \times 20}{2 \times 10} = 5 Hz .

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