In a diffraction pattern due to a single slit of width a, the first minimum is observed at an angle 30^ when light of wavelength 500 nm is incident on the slit. The first secondary maximum is observe…

Question

In a diffraction pattern due to a single slit of width a, the first minimum is observed at an angle 30^ when light of wavelength 500 nm is incident on the slit. The first secondary maximum is observed at an angle of

Accepted Answer

Correct answer: B. (b) Let first secondary maximum occur at angle _2. ∵n = asin ⁡ _1 ⇒a= nλ sin ⁡30^ =2 [ ∵n=1 ] and for maxima and _1=30^ (2n+1 ) 2=a sin ⁡ _2 ⇒ (2+1 ) 2=a sin ⁡ _2 ⇒ sin ⁡ _2= 3 2a Substituting the value of a=2 in Eq. (i), we get ∴ sin _2= 3 2 2 = 34 ⇒ _2= sin^-1 ⁡ ( 34 )

$In a diffraction pattern due to a single slit of width , the first minimum is observed at an angle when light of wavelength is incident on the slit. The first secondary maximum is observed at an angle of$

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