An elastic spring of unstretched length L and force constant k is stretched by a small length x. It is further stretched by another small length y. Work done during the second stretching is

Question

Accepted Answer

Correct answer: D. (d) Elastic potential energy of spring, W_1= 12kx^2….(i) Here, k= spring constant, x= displacement of spring Work done for displacement (x+y ) of spring, W_2= 12k (x+y )^2……(ii) Work done during second stretching = 12k (x+y )^2- 12kx^2= 12k(x^2+y^2+2 xy-x^2)= 12k(y^2+2 xy)= 12 ky [y+2x ] .

$An elastic spring of unstretched length L and force constant k is stretched by a small length x . It is further stretched by another small length y . Work done during the second stretching is$

Solution

More Work, Energy & Power PYQs