A force acts on a body of mass 10 kg, resulting in its displacement given as x= ( t^325 )m, where t is the time in seconds. The work done by the force in 5s is

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Correct answer: D. (d) Given Mass of the body, m=10 kg Displacement, x= t^325 So, velocity, v= dx dt= 3t^225 ms^-1 Acceleration, a= dv dt= 6t25 ms^-2 Force = ma=10 ( 6t25 )= 12t5N Work done in displacing object by displacement dx is dW=F . dx= mavdt ( ∵ dx= vdt )

$A force acts on a body of mass 10 kg, resulting in its displacement given as x = (\frac{t ^{3}}{25}) m, where t is the time in seconds. The work done by the force in 5 s is$

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