A block of mass 10 kg, moving in x-direction with a constant speed of 10 ms^-1, is subjected to a retarding force F=0.1 J/m during its travel from x=20 m to 30 m. Its final KE will be

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Accepted Answer

Correct answer: A. (a) From work-energy theorem, Work done = Change in KE ⇒W=K_f-K_i ⇒K_f=W+K_i = 0.05em Fxdx+ 12mv^2= 0.05em-01. xdx+ 12 10 10^2=-0.1 ( x^22 )_20^30+500=-0.05(30^2-20^2)+500=-0.05 [900-400 ]+500 ⇒K_f=-25+500=475 J

$A block of mass 10 kg, moving in x -direction with a constant speed of 10 ms^{- 1}, is subjected to a retarding force F = 0.1 \times J / m during its travel from x = 20 m to 30 m. Its final KE will be$

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