JEE Previous Year Question

The ionization enthalpy of ${\text{Na}}^{+}$formation from $N{a}_{\left(g\right)}$is 495.8 $kJ\text{mo}{l}^{-1}\text{,}$while the electron gain enthalpy of Br is $-325.0kJ\text{mo}{l}^{-1}$. Given the lattice enthalpy ofNaBris $-728.4kJ\text{mo}{l}^{-1}$. The energy for theformation of NaBr ionic solid is (-) ____$\times {10}^{-1}kJ\text{mo}{l}^{-1}$

Topic: JEE PYQ

Answer: 5576. Full step-by-step solution below.