A vessel at 1000 K contains CO_2 with a pressure of 0.5 atm. Some of CO_2 is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm, then Kp is:

Question

Accepted Answer

Correct answer: A. (a) CO_2 (g )+C (s ) ⇌2 CO (g ) 0.5 - 0.5-x 2 x P_ total=0.5+x =0.8x =0.3 K_P= (0.6 )^20.2 =1.8

$A vessel at 1000 K contains CO_{2} with a pressure of 0.5 atm. Some of CO_{2} is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm, then Kp is:$

Solution

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