In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide ( AgBr ). The percentage of Bromine in the organic compound is … … 10^-1 \% (Nearest integer). (…

Question

In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide ( AgBr ). The percentage of Bromine in the organic compound is … … 10^-1 \% (Nearest integer). (Given: Molar mass of Ag is 108 and Br is 80 g mol^-1 )

Accepted Answer

Correct answer: 255. (255) Mass of organic compound =0.25 g Mass of AgBr=0.15 g No. of moles of Br= No. of moles of AgBr= 0.15188 Mass of Br= 0.15 80188 g \% of Br= 0.15 80 100188 0.25 =25.5 \% =255 10^-1 \%

$In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide (AgBr) . The percentage of Bromine in the organic compound is \dots \dots \times 10^{- 1 %} (Nearest integer). (Given: Molar mass of Ag is 108 and Br is 80 g mol^{- 1})$

Solution

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