MereTeacher

JEE • NEET • FOUNDATION

JEE · NEET Previous Year Question

$The compound that will react most readily with NaOH to form methanol is$

Topic: JEE PYQ

Answer: C. Full step-by-step solution below.

A $(C H_{3})_{4} N^{+} I^{-}$
B $C H_{3} O C H_{3}$
C $(C H_{3})_{3} S^{+} I^{-}$
D $(C H_{3})_{3} C-Cl$

Correct answer: C

Solution

(c) Carbon-sulphur bond is weaker than carbon-nitrogen bond. So the -(C H_{3})_{2} S^{+} is a better leaving group. Therefore react most readily with NaOH to form methanol.

More General Organic Chemistry PYQs

$In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide\dots$
$Which of the following compounds is not chiral ?$
$Which among the following purification methods is based on the principle of "Solubility" in two different solvents?$
$The correct pair(s) of the ambident nucleophiles is (are): (A) AgCN / KCN (B) RCOOAg / RCOOK \dots$
$The correct decreasing order of priority for the functional groups of organic compounds in the IUPAC system of nomenclature is:$