How much amount of NaCl should be added to 600g for water ( =1.00g/ mL ) to decrease the freezing point of water to -0.2^ C ?..... (The freezing point depression constant of water =2 Kkg mol^-1

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Correct answer: 1.76. (1.76) T_f=0.2^ C T_f=ik_fm 0.2=2 2 58.5 1000600 = 0.2 58.5 6001000 4= 1.2 58.540=1.76g

$How much amount of NaCl should be added to 600 g for water (ρ = 1.00 g / mL) to decrease the freezing point of water to - 0.2^{\circ} C ? ..... (The freezing point depression constant of water = 2 Kkg mo l^{- 1}$

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