A sphere increases its volume at the rate of cc/s. The rate at which its surface area increases when the radius is 1 cm is

Question

Accepted Answer

Correct answer: A. (a) : Here, V= 43 r^3 ⇒ dV dt=4 r^2 ( dr dt ) Also, S=4 r^2 ⇒ dS dt=8 πr ( dr dt ) ⇒ dS dt=8 πr ( dV/ dt )4 r^2 [Using(1) ⇒ dS dt= 2r ( dV dt )= 21 =2 sq cm/s

$A sphere increases its volume at the rate of π cc / s . The rate at which its surface area increases when the radius is 1 cm is$

Solution

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