If the surface area of a cube is increasing at a rate of 3.6 cm^2/ sec retaining its shape; then the rate of change of its volume (in cm^3/ sec )when the length of a side of the cube is 10 cm is:

Question

Accepted Answer

Correct answer: A. (a) JEE Main 2020 For cube of side 'a’ A=6a^2 and V=a^3 Given dA dt=3.6=12a da dt dV dt=3a^2 da dt=3a^2 ( 3.612a ) At a=10 dV dt=9

$If the surface area of a cube is increasing at a rate of 3.6 cm^{2} / sec retaining its shape; then the rate of change of its volume (in cm^{3} / sec)when the length of a side of the cube is 10 cm is:$

Solution

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