The equation of the tangent to the curve y = x + 4x^2, that is parallel to the x-axis,

Question

Accepted Answer

Correct answer: C. (c)y = x + 4x^2 y′ = 1 – 8x^3 = 0 ⇒ x3 = 8 ⇒ x = 2 y = 2 + 42^2 = 3 (2, 3) is point of contact Thus y = 3 is tangent Hence correct option is (c)

$The equation of the tangent to the curve y = x + \frac{4}{x ^{2}}, that is parallel to the x-axis,$

Solution

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