If f (x )=( log ⁡xx-1 , ifx 1k , ifx=1) is continuous at x=1, then the value of k is

Question

Accepted Answer

Correct answer: C. (c): For continuity at x=1 , limf (x )=f (a ) Now, lim_x 1 0.05em log ⁡xx-1 Replacing x by 1+h, we get lim_h 0 0.05em log ⁡ (1+h )h=1=k ⇒k=1.

$If f (x) = (\frac{log x}{x - 1}, if x \neq = 1 k, if x = 1) is continuous at x = 1, then the value of k is$

Solution

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