If log_10 ⁡ ( x^2-y^2x^2+y^2 )=2, then dy dx=

Question

Accepted Answer

Correct answer: A. (a) : log_10 ⁡ ( x^2-y^2x^2+y^2 )=2 (Given) ⇒ x^2-y^2x^2+y^2=100 ⇒x^2-y^2=100x^2+100y^2 ⇒99x^2+101y^2=0 Differentiate w.r.t. x, we get 2 (99 )x+2 (101 )y dy dx=0 ⇒99x+101y dy dx=0 ⇒ dy dx=- 99x101y

$If log_{10} (\frac{x ^{2} - y ^{2}}{x ^{2} + y ^{2}}) = 2, then \frac{dy}{dx} =$

Solution

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