If f :N R is defined by f (1 )=-1 and f (n+1 )=3f (n )+2 for 1, then f is

Question

Accepted Answer

Correct answer: C. (c) Given, f :N R and f (1 )=-1 and also given that f (n+1 )=3f (n )+2 for n 1 Now, put n=1, we get f (2 ) =3f (1 )+2 =3 (-1 )+2=-1 Put n=2, we get f (3 )=3f (2 )+2=3 (-1 )+2=-1 So ,f (n )=-1 for all So, f (n )=-1 for all values of n. Hence, f (n ) is a constant function.

$If f : N \to R is defined by f (1) = - 1 and f (n + 1) = 3 f (n) + 2 for \geq 1, then f is$

Solution

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