The general solution of the differential equation 1-x^2y^2 dx=y dx+x dy is

Question

Accepted Answer

Correct answer: C. (c): Put xy=z, the given differential equation becomes 1-z^2 dx= dz ⇒ dz 1-z^2= dx Taking integral on both sides, we get sin^-1 ⁡z=x+c ⇒z= sin ⁡ (x+c ) ⇒ xy= sin ⁡ (x+c )

$The general solution of the differential equation 1 - x^{2} y^{2} \cdot dx = y \cdot dx + x \cdot dy is$

Solution

More Differential Equations PYQs