a ,b ,c ,d are arbitrary constants. Then the corresponding differential equation to y=ae^x+be^-x+ ccos ⁡x+ dsin ⁡x is

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Accepted Answer

Correct answer: A. (a) ∵y=ae^x+be^-x+ ccos ⁡x+ dsin ⁡x ⇒ y^ '=ae^x-be^-x- csin ⁡x+ dcos ⁡x ⇒ y^ ' '=ae^x+be^-x- ccos ⁡x- dsin ⁡x ⇒ y^ ' ' '=ae^x-be^-x+ csin ⁡x- dcos ⁡x ⇒y^ ' '=ae^x+be^-x+ ccos ⁡x+ dsin ⁡x ⇒y^ ' '=y

$a, b, c, d are arbitrary constants. Then the corresponding differential equation to y = a e^{x} + b e^{- x} + ccos x + dsin x is$

Solution

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