The sum of the degree and order of the differential equation (1+y_1^2)^2/3=y_2 is

Question

Accepted Answer

Correct answer: B. (b) : The given differential equation is, (1+y_1^2)^2/3=y_2 ⇒(1+y_1^2)^2=y_2^3 So, order =2, degree =3 ∴ Required sum =5

$The sum of the degree and order of the differential equation (1 + y_{1}^{2})^{2/3} = y_{2} is$