The solution curve, of the differential equation 2y dy dx+3=5 dy dx, passing through the point (0 ,1 ) is a conic, whose vertex lies on the line:

Question

Accepted Answer

Correct answer: A. (a) (2y-5 ) dy dx=-3 (2y-5 ) dy=-3 dx2 y^22-5y=-3x+ ∵ Curve passes through (0 ,1 ) ⇒ =-4 ∵ Curve will be (y- 52)^2=-3(x- 34) ∴ Vertex of parabola will be ( 34 , 52 ) ∵2x+3y=9

$The solution curve, of the differential equation 2 y \frac{d y}{d x} + 3 = 5 \frac{d y}{d x}, passing through the point (0, 1) is a conic, whose vertex lies on the line:$

Solution

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