If a and b are respectively the order and degree of a differential equation y^2 (y^ ' ' )^2+3x (y^ ' )^1/3+x^2y^2= sin ⁡x, then

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Correct answer: C. (c) y^2 (y^ ' ' )^2+3x (y^ ' )^1/3+x^2y^2= sin ⁡x Now 3x (y^ ' )^1/3= sin ⁡x-y^2 (y^ ' ' )2-x^2y^2 Now take cube on both sides we hav order of given diff. eq. =2 and degree =6 ⇒ a=2 \&b=6 and b=3a

$If a and b are respectively the order and degree of a differential equation y^{2} (y^{’ ’})^{2} + 3 x (y^{’})^{1/3} + x^{2} y^{2} = sin x, then$

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