JEE Previous Year Question∑1+2cos5xcos7x−cos8xdx=Topic: JEE PYQAnswer: B. Full step-by-step solution below.Asin2x−31sin3x+cB21sin2x−31sin3x+cC21sin2x−sin3x+cD31sin2x−21sin3x+cCorrect answer: BSolution(b)Let,I=∫1+2cos5xcos7x−cos8xdx=∫1+2−4sin2(25x)cos7x−cos8xdx=∫3−4sin2(25x)2sin215xsin2xdx=∫3sin25x−4sin325x2sin215xsin2xsin25xdx=sin215x2sin215xsin2xsin25xdx=∫2sin2xsin25xdx=∫cos2x−cos3xdx=21sin2x−31sin3x+c (∵sin3θ=3sinθ−4sin3θ)More Indefinite Integration PYQsIf ∫x71−x4dx=f(x)(1−x4)n+C, then…If…If x=1 and…∑4cos2x−5sin2xcosxdx= If…