4 cos^2 ⁡x-5 sin^2 ⁡x cos xdx=

Question

Accepted Answer

Correct answer: A. (a) 4 cos^2 ⁡ (x )-5 sin^2 ⁡ (x ) cos ⁡ (x ) dx letI= 4(1- sin^2 ⁡x)-5 sin^2 ⁡ (x ) cos ⁡ (x ) dx= 4-9 sin^2 ⁡ (x ) cos ⁡ (x ) dx put3 sin ⁡ (x )=t ⇒ cos ⁡ (x ) dx= 13 dtI= 4-t^2 13 dt= 13( t2 4-t^2+ 42 sin^-1 ⁡ ( t2 ))+c= 12 sin ⁡ (x ) 4-9 sin^2 ⁡ (x )+ 23 sin^-1 ⁡ ( 3 sin ⁡ (x )2 )+c

$\sum 4 cos^{2} x - 5 sin^{2} x cos xdx =$

Solution

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