If limx 0 0.05em ax-(e^4x-1) ax(e^4x-1)exists and is equal to b, then the value of a-2b is

Question

Accepted Answer

Correct answer: 5. 5 JEE Main 2021 limx 0 0.05em ax-(e^4x-1) ax(e^4x-1) Applying L^ ' ' Hospital Rule limx 0 0.05em a-4e^4xa(e^4x-1)+ ax ⁡ (4e^4x ) so a=4 Applying L^ ' Hospital Rule x 0 -16e^4xa (4e^4x )+a (4e^4x )+ ax (16e^4x ) -164a+4a= -1632=- 12=b a-2b=4-2 ( -12 )=4+1=5

$If lim x \to 0 \frac{ax - ( e ^{4 x} - 1 )}{ax ( e ^{4 x} - 1 )} exists and is equal to b, then the value of a - 2 b is$

Solution

More Limits PYQs