lim_x 0 0.05em 2 sin ⁡x- sin ⁡2xx^3 is equal to

Question

Accepted Answer

Correct answer: A. (a) Let l= lim_x 0 0.05em 2 sin ⁡x- sin ⁡2xx^3 ( 00 ) form ) (using L-Hospital rule) = limx 0 0.05em 2 cos ⁡x-2 cos ⁡2x3x^2 ( 00 form ) ( usingL- Hospital rule ) = limx 0 0.05em -2 sin ⁡x+4 sin ⁡2x6x ( 00 form ) ( usingL- Hospital rule ) = limx 0 0.05em -2 cos ⁡x+8 cos ⁡2x6= -2+86=1

$lim_{x \to 0} \frac{2 sin x - sin 2 x}{x ^{3}} is equal to$

Solution

More Limits PYQs