JEE Previous Year Questionlimx→0(7x2+23x2+2)x21 is equal toTopic: JEE PYQAnswer: A. Full step-by-step solution below.Ae−2Be2Ce2/7De3/7Correct answer: ASolution(a)LetL=limx→0(7x2+23x2+2)x21=elimx→0x21(7x2+23x2−2−1)=elimx→0x21(7x2+2−4x2)=e2−4=e−2More Limits PYQsLet f(x)=sinx,g(x)=cosx,h(x)=x2 then…limx→01+x2+x4−1x(ex(1+x2+x4−1)−1)Let…limx→1x−1tan(x2−1) is equal toLet f be a differentiable function on R such that f(2)=1,f’(2)=4. Let…