JEE Previous Year Questionlimx→2π((x−2π)21∫x3(2π)3cos(t31)dt) is equal toTopic: JEE PYQAnswer: C. Full step-by-step solution below.A83πB43π2C83π2D43πCorrect answer: CSolution(c) Using L'hospital rule=limx→2π−2(x−2π)0−cosx×3x2=limx→2π−2(x−2π)sin(x−2π)×43π2=83π2More Limits PYQsLet f(x)=sinx,g(x)=cosx,h(x)=x2 then…limx→01+x2+x4−1x(ex(1+x2+x4−1)−1)Let…limx→1x−1tan(x2−1) is equal toLet f be a differentiable function on R such that f(2)=1,f’(2)=4. Let…