The Cartesian form of the curve given by x= a2(t+ 1t), y= a2(t- 1t) ,t is a parameter, is

Question

Accepted Answer

Correct answer: B. (b) x= a2(t+ 1t) … … … … … … . . (i )y= a2(t- 1t) … … … … … … ( ii ) Eq. (i)^2 -(ii)^2 ⇒x^2-y^2 = a^24(t+ 1t)^2- a^24(t- 1t)^2= a^24(t^2+ 1t^2+2-t^2- 1t^2+2)= a^24 (2+2 )= a^24 4 ⇒x^2-y^2=a^2

$The Cartesian form of the curve given by x = \frac{a}{2} (t + \frac{1}{t}), y = \frac{a}{2} (t - \frac{1}{t}), t is a parameter, is$

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