For the parabola y^2=4x, the point P whose focal distance is 17 , is

Question

Accepted Answer

Correct answer: B. (b) : Let the coordinates of point P on the parabola be (t^2 ,2t ), focus is (1 ,0 ) ∴ Focal distance = (t^2-1)^2+ (2t-0 )^2=17 ⇒ t^4+2t^2+1=17 ⇒(t^2+1)=17 ⇒t^2=16 ⇒t= 4 So coordinates of point P are (16 ,8 ) or (16 ,-8 ).

$For the parabola y^{2} = 4 x, the point P whose focal distance is 17 , is$

Solution

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