Let the parabola y=x^2+px-3, meet the coordinate axes at the points P ,Q and R . If the circle C with centre at (-1 ,-1 ) passes through the points P ,Q and R, then the area of △ PQR is:

Question

Accepted Answer

Correct answer: C. (c) y=x^2+ px-3 Let P ( ,0 ) ,Q ( ,0 ) ,R (0 ,-3 ) Circle with centre (-1 ,-1 ) is (x+1 )^2+ (y+1 )^2=r^2 Passes through (0 ,-3 ) (1^2+ (-2 )^2=r^2) r^2=5 (x+1 )^2+ (y+1 )^2=5 Put y=0 (x+1 )^2=5-1 (x+1 )^2=4 x+1= 2 x=1 or x=-3 ∴P (1 ,0 ) and Q (-3 ,0 ) Area of △ PQR= 12(101-3010-31)=6

$Let the parabola y = x^{2} + p x - 3, meet the coordinate axes at the points P, Q and R . If the circle C with centre at (- 1, - 1) passes through the points P, Q and R, then the area of △ PQR is:$

Solution

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