Let n be a non-negative integer. Then the number of divisors of the form “4n+1” of the number (10)^10.(11)^11.(13)^13 is equal to

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Accepted Answer

Correct answer: 924. (924) N = 2^10 × 5^10 × 11^11 × 13^13 Now, power of 2 must be zero, power of 5 can be anything, power of 13 can be anything. But, power of 11 should be even. So, required number of divisors is 1 × 11 × 14 × 6 = 924

$Let n be a non-negative integer. Then the number of divisors of the form “4n+1” of the number (10)^{10} . (11)^{11} . (13)^{13} is equal to$

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