If the function f (x )= log ⁡ (1+ ax )- log ⁡ (1- bx )x, x 0 is continuous at x=0, then f (0 )=

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Correct answer: B. (b) : If f (x ) is continuous at x=0, then lim_x 0 0.05emf (x )=f (0 ) ∴f (0 )= lim_x 0 0.05em log ⁡ (1+ ax )- log ⁡ (1- bx )x = lim_x 0 0.05em log ⁡ (1+ ax )x- lim_x 0 0.05em log ⁡ (1- bx )x = lim_x 0 0.05em a1+ ax+ lim_x 0 0.05em b1+ bx [By L.H. Rule] =a+b

$If the function f (x) = \frac{log ( 1 + ax ) - log ( 1 - bx )}{x}, x \neq = 0 is continuous at x = 0, then f (0) =$

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