Let , , be three non-zero real constants and a ,b ,c De three arbitrary real numbers which satisfy aa+ βb+ γc= 0 . Then the point of concurrence of the family of lines ax+ by+c=0 is

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Correct answer: D. (d) Given a+ b+ c=0 ⇒c= ( - )a- ( )b how, family of lines is given by an equation c=- ax- by ⇒x= ,y= Thus ( , ) is the point of concurrency.

$Let α, β, γ be three non-zero real constants and a, b, c De three arbitrary real numbers which satisfy aa + βb + γc = 0 . Then the point of concurrence of the family of lines ax + by + c = 0 is$

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