The point to which the origin should be shifted so that the equation y^2-6y-4x+13=0 is transformed to the form y^2+ Ax=0 is

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Correct answer: C. (d) Given equation is y^2-6y-4x+13=0 ⇒ (y-3 )^2=4 (x-1 ) ⇒ (y-3 )^2-4 (x-1 )=0 Hence, it we shift the origin to (-1 ,3 ), then it transformed to the y^2+4x=0

$The point to which the origin should be shifted so that the equation y^{2} - 6 y - 4 x + 13 = 0 is transformed to the form y^{2} + Ax = 0 is$

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